9x^2+x+9x^2=0

Solution for 9x^2+x+9x^2=0 equation:

9x^2+x+9x^2=0

We add all the numbers together, and all the variables

18x^2+x=0

a = 18; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·18·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*18}=\frac{-2}{36}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*18}=\frac{0}{36}
=0
$